Finding slope fields using Euler method

Click For Summary
To find the slope field for the differential equation dy/dt = 2t + 1, plot short line segments with slope 2t + 1 at various points in the t-y coordinate system, as the slope does not depend on y. Starting from the initial condition y(-2) = -2, sketch a curve that is tangent to these segments, which will represent the solution y = t^2 + t - 4. Euler's method is not used to solve the slope field itself, but rather to provide a numerical approximation to the solution of the differential equation. This method involves iterating through points to estimate the curve based on the slope at each point. Understanding these concepts is crucial for effectively working with differential equations and their graphical representations.
Philip Wong
Messages
95
Reaction score
0
hi guys,

can someone give me a quick tutorial on how to solve and explain to me the concept of slope field of the following differential equation:
sketch the slope field for dy/dt = 2t+1
showing the solution y=t^2+t-4, which satisfies the initial condition y(-2)= -2


Also how to use the Euler's method to solve the slope field of the above differential condition.

thanks!
 
Mathematics news on Phys.org
Choose a number of points in a ty- coordinate system (t is the horizontal axis, y the vertical axis. At each (t, y) point, draw a short line segment having slope 2t+ 1. Since that does not depend on y, you can do that by marking lines with the same slope in a vertical "stack".

Now, starting at the point (-2, -2), draw a curve that is always tangent to those line (use the short lines to give the direction at each point). The curve should look like y= t^2+ t- 4.<br /> <br /> You <b>don&#039;t</b> use Euler&#039;s method to &quot;solve the slope field&quot;. Euler&#039;s method is used to find a numerical approximation to the solution to a differential equation problem.
 
Here is a little puzzle from the book 100 Geometric Games by Pierre Berloquin. The side of a small square is one meter long and the side of a larger square one and a half meters long. One vertex of the large square is at the center of the small square. The side of the large square cuts two sides of the small square into one- third parts and two-thirds parts. What is the area where the squares overlap?

Similar threads

  • · Replies 7 ·
Replies
7
Views
4K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 5 ·
Replies
5
Views
10K
  • · Replies 38 ·
2
Replies
38
Views
11K
  • · Replies 7 ·
Replies
7
Views
4K
Replies
20
Views
4K
  • · Replies 8 ·
Replies
8
Views
3K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 16 ·
Replies
16
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K