Finding Slopes and Equations of Secant and Tangent Lines for a Given Curve

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To find the slope of the secant line and the equation of the tangent line for the curve defined by x^2 - 5x - 4 at the point P(3, 10), the slope of the tangent line is determined using the derivative, which is f'(x) = 2x - 5. At x = 3, this gives a slope of 1 for the tangent line. The equation of the tangent line can be expressed as y - 10 = 1(x - 3), simplifying to y = x + 7. The slope of the secant line between P(3, 10) and another point on the curve is also discussed, emphasizing that it intersects two points of the curve. Understanding these concepts is crucial for solving problems involving secant and tangent lines.
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Homework Statement


Given a point P (3, 10) and the equation of a curve as x^2 -5x-4, find the slope of the secant and the equation of the tangent line to the curve


Homework Equations





The Attempt at a Solution


I tried using y = f(x + h) -f(x) all divided by h and got (x + h)^2 - 5(x + h) - 4 -x^2 - 5x-4 all divided by h

I got x^2 + 2xh + h^2 - 5x-5h -4-x^2 -4 all divided by h

which equals 2xh + h^2 - 5x-5h - 4+5x + 4 all divided by h

which equals 2x + h all divided by h

Can we then claim that the slope of the secant is probably 2 and substitute this into an equation of the form
y - 10 = 2(x-3)
or y = 2(x-3) + 10 to get the equation of the tangent line
 
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Jan Hill said:

Homework Statement


Given a point P (3, 10) and the equation of a curve as x^2 -5x-4, find the slope of the secant and the equation of the tangent line to the curve


Homework Equations





The Attempt at a Solution


I tried using y = f(x + h) -f(x) all divided by h and got (x + h)^2 - 5(x + h) - 4 -x^2 - 5x-4 all divided by h
Jan Hill said:
I got x^2 + 2xh + h^2 - 5x-5h -4-x^2 -4 all divided by h

which equals 2xh + h^2 - 5x-5h - 4+5x + 4 all divided by h

which equals 2x + h all divided by h
Lets' start by writing this in a more mathematical form.
[f(x + h) -f(x)]/h = [(x + h)^2 - 5(x + h) - 4 - ([/color]x^2 - 5x-4)[/color]]/h

Jan Hill said:
Can we then claim that the slope of the secant is probably 2 and substitute this into an equation of the form
y - 10 = 2(x-3)
or y = 2(x-3) + 10 to get the equation of the tangent line
 
so simplified this becomes

the limit as h approaches 0 of 2x + h - 5

which becomes 2x - 5

but what is the slope of the secant?
 
Yes, so f'(x) = 2x - 5. This is the slope of the tangent line at a point (x, f(x)).

A secant line is a line that intersects two points of a curve.

I think what the first part of this problem is asking you to do is to find the slope of the secant line between P(3, 10) and a point (x, f(x)).

The second part is asking you for the slope of the tangent line at (3, 10), I think.

Have you written the problem here exactly as it's worded?
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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