1. The problem statement, all variables and given/known data To determine the Specific heat of an oil , an electrical heating coil is placed in a calorimeter with 380g of the oil at 10C. The coil consumes energy(and gives off heat) at the rate of 84W. After 3min the oil temperature is 40C. If the water equivalent of the calorimeter and coil is 20g, what is the specific heat of the coil? 2. Relevant equations Q=mc(deltaT) H=Q/change in time 3. The attempt at a solution Q=Ht=3min(60s)(84W)=15120J 15120=380cm(c)(40-10C)+20cm(1)(40-10C) I have been at this problem for HOURS the answer is 0.26 cal/g*C. Also I don't really know what "water equivalent of the calorimeter and coil" means. I would think the final temp after 3min of heating is the total heat but obviously I am wrong PLEASE HELP!