1. The problem statement, all variables and given/known data A 34 g block of ice is cooled to -75°C. It is added to 562 g of water in an 80 g copper calorimeter at a temperature of 22°C. Find the final temperature. (The specific heat of copper is 387 J/kg ·°C and the specific heat of ice is 2090 J/kg ·°C. The latent heat of fusion of water 3.33 x 10^5 J/kg and the specific heat of water is 4186 J/kg ·°C.) Answer in units of °C. 2. Relevant equations 1,000 g= 1 kg Q= mcdeltaT Qice + Qlost H20 + Qcopper containter =0 mcdeltaT of ice + mL of ice + Qlost H20 + Qcopper container =0 3. The attempt at a solution I tried the last equation. .034(2090) (75) + (.034) (3.33e-9) + (.562)(4186)(Tf-22) + (.08)(387)(Ttf-22)=0 and i got 134.28 C which was wrong. Help!