Specific heat problem finding final temp with calorimeter system

In summary, a 34 g block of ice at -75°C is added to 562 g of water at 22°C in an 80 g copper calorimeter. The final temperature is determined using the equations Q= mcdeltaT, Qice + Qlost H20 + Qcopper containter =0, and mcdeltaT of ice + mL of ice + Qlost H20 + Qcopper container =0. The final temperature is found to be 134.28°C.
  • #1
bam09
2
0

Homework Statement



A 34 g block of ice is cooled to -75°C. It is added to 562 g of water in an 80 g copper calorimeter at a temperature of 22°C. Find the final temperature. (The specific heat of copper is 387 J/kg ·°C and the specific heat of ice is 2090 J/kg ·°C. The latent heat of fusion of water 3.33 x 10^5 J/kg and the specific heat of water is 4186 J/kg ·°C.) Answer in units of °C.



Homework Equations



1,000 g= 1 kg

Q= mcdeltaT

Qice + Qlost H20 + Qcopper containter =0

mcdeltaT of ice + mL of ice + Qlost H20 + Qcopper container =0



The Attempt at a Solution



I tried the last equation.

.034(2090) (75) + (.034) (3.33e-9) + (.562)(4186)(Tf-22) + (.08)(387)(Ttf-22)=0

and i got 134.28 C which was wrong. Help!
 
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  • #2
Check the signs of the dT
which have heat flowing in and which out
 
  • #3
i actually just got the answer, but thanks!
 

FAQ: Specific heat problem finding final temp with calorimeter system

1. What is specific heat and why is it important in calorimeter systems?

Specific heat is the amount of heat energy required to raise the temperature of 1 gram of a substance by 1 degree Celsius. It is important in calorimeter systems because it helps us determine the amount of heat absorbed or released by a substance during a reaction, which can help us understand its properties and behavior.

2. How do you calculate the final temperature in a calorimeter system?

The final temperature in a calorimeter system can be calculated using the formula Q = mCΔT, where Q is the heat absorbed or released, m is the mass of the substance, C is the specific heat, and ΔT is the change in temperature. This formula takes into account the heat exchange between the substances in the system and can help us find the final temperature.

3. Is the specific heat of a substance always the same?

No, the specific heat of a substance can vary depending on its physical and chemical properties. For example, the specific heat of water is different from the specific heat of iron. It can also change with temperature and pressure.

4. Can a calorimeter system be used to determine the specific heat of a substance?

Yes, a calorimeter system can be used to determine the specific heat of a substance. By measuring the heat exchange and changes in temperature, we can use the formula Q = mCΔT to calculate the specific heat of the substance being tested.

5. What are the limitations of using a calorimeter system to find the final temperature?

One limitation of using a calorimeter system is that it assumes that there is no heat loss to the surroundings during the reaction. In reality, there is always some heat loss, which can affect the accuracy of the final temperature calculation. Additionally, the specific heat of a substance may not remain constant throughout the reaction, leading to errors in the final temperature calculation.

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