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serverxeon
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Homework Statement
Given a certain mass m is hung from a spring,
Find spring constant.
mg=kx or 1/2kx^2 = mgh?
These two give very different results for k, but I can't tell which is right or wrong!
serverxeon said:Given a certain mass m is hung from a spring,
Find spring constant.
The spring constant of a hung mass refers to the stiffness or rigidity of the spring that is supporting the mass. It is a measure of how much force is required to stretch or compress the spring by a certain distance.
The spring constant can be calculated by dividing the force applied to the spring by the displacement caused by the applied force. This can be represented by the equation: k = F/x, where k is the spring constant, F is the force applied, and x is the displacement.
The unit of measurement for spring constant is Newtons per meter (N/m) in the SI system. In the Imperial system, it is measured in pounds per inch (lb/in).
No, the spring constant of a hung mass does not change over time. It is a characteristic property of the spring and is dependent on factors such as the material and shape of the spring, but not on time.
The spring constant affects the motion of a hung mass by determining the frequency and amplitude of oscillations. A higher spring constant will result in a shorter period of oscillation and a smaller amplitude, while a lower spring constant will result in a longer period and a larger amplitude.