- #1

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It says that to find the Taylor series of sin(2x + 1) around the point x = 0, we cannot just substitute 2x+1 into the Maclaurin series for sinx because 2x + 1 doesn't approach a limit of 0 as x approaches 0.

It says we have to find the Taylor series for sinx about x = 1, and then we can substitute 2x + 1 into it.

Why is this?