- #1
JG89
- 728
- 1
In this: http://www.math.tamu.edu/~fulling/coalweb/sinsubst.pdf
It says that to find the Taylor series of sin(2x + 1) around the point x = 0, we cannot just substitute 2x+1 into the Maclaurin series for sinx because 2x + 1 doesn't approach a limit of 0 as x approaches 0.
It says we have to find the Taylor series for sinx about x = 1, and then we can substitute 2x + 1 into it.
Why is this?
It says that to find the Taylor series of sin(2x + 1) around the point x = 0, we cannot just substitute 2x+1 into the Maclaurin series for sinx because 2x + 1 doesn't approach a limit of 0 as x approaches 0.
It says we have to find the Taylor series for sinx about x = 1, and then we can substitute 2x + 1 into it.
Why is this?