(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

What is the temperature in K of 1.0 kg of lead initially at 300 K after it falls 200 m? The specific heat of lead is 128 J/kg C.

a) 307 b) 311 c) 315 d)275 e) 279

the answer my teacher said was c but i keep getting a.

2. Relevant equations

I thought I would use mc (Tf-Ti) = mgy

3. The attempt at a solution

The masses cross out. so

(300)(delta T) = (9.8)(200)

I get delta T = 6.53

300 +6.53 = 306.53

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# Homework Help: Finding temperature after something falls

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