Finding tension in cords with given resultant force

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The discussion revolves around calculating the tension in cord 2 while dragging a crate with a known resultant force and tension in cord 1. Participants emphasize the importance of using vector addition to analyze the forces acting on the crate. They suggest breaking down the resultant force into its x and y components to solve for the unknown tension. One user initially struggles with the concept but later confirms they have resolved the issue with assistance. The conversation highlights the necessity of understanding vector components in physics problems.
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Homework Statement


A crate is being dragged across a horizontal icy sidewalk by two people pulling horizontally on cords. the net horizontal force on the crate is 56N 16 degrees S of E. The tension in cord 1 is 27N [E]. if friction is negligible, determine the tension in cord 2

Homework Equations



use component method

The Attempt at a Solution



like i don't know how to get the tension 2
 

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The resultant force and the force in cord 1 is given. Draw a sketch. Tell us what you know about vector addition.
 


PhanthomJay said:
The resultant force and the force in cord 1 is given. Draw a sketch. Tell us what you know about vector addition.

well here is my sketch don't know if it is right or not and to be honest i do not know much about vector addition just that when you have all your forces on the x or y you add them together
 

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jasonbans said:
well here is my sketch don't know if it is right or not and to be honest i do not know much about vector addition just that when you have all your forces on the x or y you add them together
The problem is perhaps a bit unclear. The forces are applied parallel to the ground. The resultant force (the sum of the 2 vectors) is given. What you have shown as T2 is actually the resultant force. You must calculate the x and y components of the resultant force. Then the x components of each of the cord forces add up to give the x comp of the resultant, and the y comp of each cord force add up to the y comp of the resultant. This will allow you to solve for the x and y comp of T2, from which you can find the mag of T2.
 


can you draw an example?
 
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PhanthomJay said:
The problem is perhaps a bit unclear. The forces are applied parallel to the ground. The resultant force (the sum of the 2 vectors) is given. What you have shown as T2 is actually the resultant force. You must calculate the x and y components of the resultant force. Then the x components of each of the cord forces add up to give the x comp of the resultant, and the y comp of each cord force add up to the y comp of the resultant. This will allow you to solve for the x and y comp of T2, from which you can find the mag of T2.

is my diagram correct? Nvm i finally figured it out thank you for the help
 

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The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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