# Finding tension in string in vertical circle

## Homework Statement

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Your niece finds her father's watch. The light watch chain has a length of 48 cm, and the mass of the watch is 270 g. Your niece swings the watch in a vertical circle, maintaining the speed of the watch at 2.3 m/s. Find the tension in the chain when it makes an angle of 43° with respect to the vertical. (Assume the watch is closer to the top of the circle than the bottom. Also assume the radius of the circle is 48 cm.)

Fnet = ma
a = v^2/r

## The Attempt at a Solution

$Fnet = ma = T + Wcos(43)$
$0.270(2.3^2 /0.48) = T + 0.270*9.8*cos(43)$
$T = 1.04 N$

This answer is incorrect. Can someone explain why?