Finding the acceleration vector component

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To find the acceleration component of a ball traveling vertically upward with quadratic air resistance, the equation of motion is established as ma = -mg - C^2D^2V^2. The user initially attempted to integrate to find velocity, but it was pointed out that the problem specifically asks for acceleration, not velocity. The correct approach involves differentiating the derived equation for motion to obtain the acceleration component. Despite following this method, the user is still not arriving at the expected answer and seeks clarification on their approach. Understanding the distinction between acceleration and velocity is crucial for solving the problem correctly.
jimmy42
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Homework Statement



A ball travels vertically upward with quadratic air resistance, find the acceleration component.

Homework Equations



So, I have x pointing vertically downward and

C=0.20 D = Diameter V=velocity

W= -mgi
R = -C^2D^2V^2

F=ma

ma= -mg-C^2D^2V^2


The Attempt at a Solution




a(t)= dv/dt

dv/dt = (-mg-C^2D^2V^2)/m


After doing the integration it seems not to make any sense. Any help where I have gone wrong? Am I along the right lines?
 
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Well, why are you integrating? The problem, according to you, asks for the acceleration, not the velocity.
 
OK, I think that just got me the equation for the acceleration of a resisted projectile

r(t)= -g - (c*D^2*v/m)

So, differentiating this twice should give the acceleration componet? I know the answer I should get and it does not match. Any help?
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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