Finding the Angle of a Bar PQ using Geometry and Theta

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SUMMARY

The discussion focuses on determining the angle of bar PQ using geometric principles and angular motion equations. The key equation referenced is aA = aB + α x rA/B + ω x (ω x rA/B), which relates linear and angular acceleration. The user expresses confusion regarding the calculation of angular acceleration, suggesting it may be zero due to constant angular velocity of point OQ. However, they conclude that geometry should be employed to express the angle of bar PQ as a function of theta.

PREREQUISITES
  • Understanding of angular motion equations, specifically aA = aB + α x rA/B + ω x (ω x rA/B)
  • Basic knowledge of geometry related to angles and triangles
  • Familiarity with the concept of angular velocity and acceleration
  • Ability to manipulate vector cross products in physics
NEXT STEPS
  • Study the application of angular motion equations in rigid body dynamics
  • Learn about the relationship between angular velocity and angular acceleration
  • Explore geometric methods for solving problems involving angles in physics
  • Investigate the implications of constant angular velocity on linear motion
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and angular motion, as well as educators looking for examples of geometric applications in physics problems.

whitejac
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Homework Statement


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Homework Equations


I want to say I should be using this one:
aA = aB + α x rA/B + ω x (ω x rA/B)

The Attempt at a Solution


The only problem is that if I'm supposed to find the angular acceleration then i'd have to take the... inverse of the cross product? To get it back and I don't think that that's possible. I also want to say that it's zero because OQ moves with constant angular velocity, but I believe that that would result in PQ moving with acceleration because theta would be changing?
 
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I don't think that equation will help.
Just use a bit of geometry to find the angle of the bar PQ as a function of theta.
 

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