Finding the Angle: Solving Trig Problems on the Ferris Wheel

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SUMMARY

The discussion centers on solving a trigonometric problem related to a Ferris Wheel designed by George Ferris in 1893, which has a diameter of 250 feet and completes one revolution every 50 seconds. The height of a seat on the Ferris Wheel is modeled by the function h(t) = 125sin(pi/25t - pi/2) + 125. The key question is determining the time (t) when a passenger is exactly 125 feet above the ground during the first 50 seconds of the ride. Visual aids, such as diagrams, are recommended to facilitate understanding of the problem.

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urthatarget
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I have this question in my trig/pre cal class and I have no idea how to approach it what so ever.

In 1893, George Ferris engineered the Ferris Wheel. It was 250 feet in diameter. If the wheel makes 1 revolution every 50 seconds, then

h(t) = 125sin (pi/25t - pi/2) + 125

represents the height (h), in feet, of a seat on the wheel as a function of time (t), where t is measured in seconds. The ride begins when t = 0.


a.) During the first 50 seconds of the ride, at what time (t) is an individual on the Ferris Wheel exactly 125 feet above the ground?

Thank you!
 
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Sometimes a diagram of the problem helps visualise the solution.
Draw the ferris wheel, add a line 125 feet off the ground, and find out what angle of rotation will bring the passenger to that height.
I have to stop now, and leave you with something to do!
 

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