Hi all, I've been attempting this problem for hours and I believe I am using the correct method, but I keep on getting the wrong answer, ANY help as to what I am doing wrong is greatly appreciated. The question is: Sketch the region enclosed by the given curves. Decide whether to integrate with respect to x or y. Then find the area of the region. 2y = 3sqrt(x) , y = 5, and 2y + 4x = 7 I've plotted the graph, and found the intersection points, with are : x= -3/4 , x=1 x= 11.11111 I integrated with respect to X (I know that y would be easier, but I'm not too sure how to do that yet), therefore, the areas were: step 1: int. between -3/4 to 1 with the function to be integrate being : 5-(-2x+7) and step 2: int. between 1 to 11.11111111 with the function to be integrated being : 5-([3sqrt(x)]/2) I integrated step 1 (2x-2, integrate that, and I got x^2-2x), when plugging in the numbers, I got -3.0625 I integrated step 2, and got 5x-x^3/2, when plugging in the numbers, I got 14.51851852 I added both areas and got 11.45601. What am I doing wrong?..