1. The problem statement, all variables and given/known data Find the area enclosed inside r=3 sin (theta) 2. Relevant equations integral? 3. The attempt at a solution basically, I took [tex]\int3sin\Theta[/tex] from 0 to 2pi, then pulled the 3 out to get [tex]3\int sin\Theta[/tex] from 0 to 2pi and then [tex]3[-cos(\Theta)][/tex] evaluated from 0 to 2pi. that seems too easy. what am I missing?
Who said everything has to be super hard? But if you work that out, you'll get 0 for the area. Is that right? It might help to draw a picture. And, hey, area in polar coordinates isn't the integral of r dtheta, is it? Would you look up the right formula for area?
Well, actually, Dick, area in polar coordinates is r dtheta! You didn't say quite what you meant to, did you?
The integral of r*dtheta*dr is the area. Not the integral of r*dtheta. I missed it at my first reading as well.