- #1

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- Thread starter satxer
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- #2

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You can always get the radius from circle equations !!

However, all circle equations are integrated by trigonometric substitution

and it can also be done by integration by parts but that is a bit tricky!!

- #3

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The equation of a half-circle (assuming (y-b) is always positive and that you don't understand that r is the radius):

[tex]\left(x-a\right)^2+\left(y-b\right)^2=r^2[/tex]

So the area of a circle is equal to: [tex]2\int_{-r-a}^{r-a}y_{(x)}dx[/tex]

That's a complicated way, but I guess it can be done.

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