Finding the B-field at a point outside ring of current IN Plane of ring

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SUMMARY

The discussion focuses on calculating the magnetic field (B-field) at a point P located outside a current-carrying ring, specifically in the plane of the ring. The Biot-Savart law is applied, with the equation db = (μI/4πr²)dl sin(x) being central to the calculations. The user encounters difficulties in integrating the expression due to the challenge of expressing the angle y in terms of x. A hint is provided to assist in visualizing the geometry of the problem, specifically the coordinates of point P and the tangent at point Q.

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Homework Statement



Determine the B field at a point P with distance d from centre of current ring radius r (d>r ie outside ring of current) but IN the Plane of ring (i.e off the axis)

Homework Equations



Biot savart: db=(u.I/4pi.r^2).dl.sinx

u=mu, I=current, x=angle made with current vector element dl and vector r connecting P to dl.

The Attempt at a Solution



the angle x will vary at all points along ring with vector joining point P, as will r.

I will integrate from 0 to 2pi my expression for db but with r^2=a^2+d^2-2adcosy

where y is angle between radial vector and d.

I am stuck because cannot determine how to express y in terms of x. and thus cannot integrate!

many thanks!
 
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maxmax1 said:
I am stuck because cannot determine how to express y in terms of x. and thus cannot integrate!

Hi maxmax1! :smile:

Hint: P is at (d,0).

The tangent at Q = (r cosy, r siny) is … ?

So the angle betweent he tangent and PQ is … ? :smile:
 

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