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Finding the charge and initial position, electric potential problem.

  1. Feb 18, 2010 #1
    The electric potential a distance r from a point charge q is 2.40×104 V.
    One meter farther away from the charge the potential is 6500 V.


    2. Relevant equations
    V=kq/r


    3. The attempt at a solution
    6500 = 8.99x10^9 (q) / 1m
    q = 7.230 x 10^-7
    then,
    r= kq/v
    r= 8.99x10^9 (7.230 x 10^-7) / 2.40×104
    r= 0.27.
     
  2. jcsd
  3. Feb 19, 2010 #2
    your solution looks fine :) .. so what is your question ..
     
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