Finding the charge and initial position, electric potential problem.

[sukdede]

The electric potential a distance r from a point charge q is 2.40×104 V.
One meter farther away from the charge the potential is 6500 V.

Homework Equations

V=kq/r

The Attempt at a Solution

6500 = 8.99x10^9 (q) / 1m
q = 7.230 x 10^-7
then,
r= kq/v
r= 8.99x10^9 (7.230 x 10^-7) / 2.40×104
r= 0.27.

 

[thebigstar25]

your solution looks fine :) .. so what is your question ..