Finding the coefficient of friction of a block on a table

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SUMMARY

The discussion focuses on calculating the coefficient of kinetic friction between block A and a table, given that block B is in downward motion at a constant speed. The key takeaway is that both blocks are in dynamic equilibrium, meaning their net forces are zero. The solution involves equating the tension in the rope for both blocks and ultimately finding that the coefficient of friction, μ, is equal to the weight of block B (Wb) divided by the weight of block A (Wa).

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Familiarity with free body diagrams
  • Knowledge of kinetic friction and its equation, fk = μkn
  • Basic concepts of dynamic equilibrium
NEXT STEPS
  • Study the principles of dynamic equilibrium in physics
  • Learn how to draw and analyze free body diagrams
  • Explore the relationship between weight, tension, and friction in pulley systems
  • Review examples of calculating coefficients of friction in various scenarios
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Students studying physics, particularly those focusing on mechanics and friction, as well as educators looking for practical examples of dynamic equilibrium and friction calculations.

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Homework Statement


Block A is on a table and is connected by a pulley to block B.
Block A has weight Wa and block B has weight Wb. Once block B is set into downward motion, it descends at a constant speed. Assume that the mass and friction of the pulley are negligible.

Calculate the coefficient of kinetic friction between block A and the table top.
Express your answer in terms of some or all of the variables Wa , Wb, and g (the acceleration due to gravity).

Homework Equations


fk=\mukn

I have gotten this hint (mastering physics problem):

In this problem, blocks A and B are in dynamic equilibrium; their velocities are constant. This means that the net force on each,F net , is equal to zero.

The tension is constant throughout the rope. By setting the sum of the forces acting on both blocks A and B equal to zero, you should be able to obtain two different expressions for the tension in the rope. Set these equal to each other and solve for \mu.


The Attempt at a Solution


I really don't know how to go about starting this. I know the equation above but don't know what to do with it. I feel like I need to know the acceleration. How would I find the tension?

Please help! Thanks!
 
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ssj2pizza said:
I really don't know how to go about starting this. I know the equation above but don't know what to do with it.

You don't know what to do with it? :eek: Haven't you ever seen a free body diagram? Don't you think it would be a good idea to draw one?

I feel like I need to know the acceleration.

You DO know the acceleration! In your very own words:

...it descends at a constant speed[/color]...

and

I have gotten this hint (mastering physics problem):

In this problem, blocks A and B are in dynamic equilibrium; their velocities are constant[/color].
 
Ok so their accelerations were equal to zero and their net forces were also equal to zero. Thanks about the free boday diagram (duh). Well i figured out the answer. It ended up being the weight of block b divided by the weight of block a. I have tried looking in my book and looking through my notes but there were no examples for finding the coefficient of friction. (frustrating)
 

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