A 100 kg bale of hay falls off a truck traveling along a level road at 24.4 m/s. It lands flat on the road and slides 100m before coming to rest. Assume the acceleration is constant, compute the coefficeient of kinetic friction between the road and the hay.
F=u x N
Sum of the forces horizontally (x) = 2440 N -f = ma (acceleration is a constant)
Sum of the forces Vertically (y) = N-W=O
The Attempt at a Solution
W= -980 so N= -980
now i plugged into f= u x N
(2440/100a)= u x -980
Now i know the answer because i can see it in the back of the book, and this doesnt feel right. advice?