Finding the Coefficient of Static Friction for a Cube

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SUMMARY

The discussion focuses on determining the coefficient of static friction for a cube subjected to a horizontal pull. It establishes that the cube will either slide or tip over depending on the height at which the force is applied. The critical conditions are defined: for sliding, the force must be less than the product of the coefficient of static friction and the normal force, while for tipping, the torque due to the applied force must exceed the torque due to gravity. The analysis emphasizes the relationship between the applied force, the height of application, and the resulting torques.

PREREQUISITES
  • Understanding of static friction and its coefficient
  • Knowledge of torque and its calculation
  • Familiarity with Newton's laws of motion
  • Basic principles of equilibrium in physics
NEXT STEPS
  • Derive the formula for the coefficient of static friction in terms of applied force and normal force
  • Explore the concept of torque in rotational dynamics
  • Study the conditions for equilibrium in rigid bodies
  • Investigate the effects of varying the height of force application on stability
USEFUL FOR

Students studying physics, particularly those focusing on mechanics, as well as educators seeking to explain the principles of static friction and torque in real-world applications.

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Homework Statement


A cube of side l rests on a rough floor. It is subjected to a steady horizontal pull F, exerted a distance h above the floor as shown below. As F increases, the block will either begin to slide, or begin to tip over and thus rotate. Determine the coefficient of static friction so that (a) the block begins to slide rather than tip; (b) the block begins to tip. [Hint: Where will the normal force on the block act if it tips?]


Homework Equations


No movement
F< Us
Movement
F>Us

The Attempt at a Solution


I know the higher you push on the cube the more likely the cube is to move or tip over. When you push low on the cube the harder it is to move and less likely it is to tip. How would I derive some kind of formula for this? I don't have any numbers, I just need formulas.
 
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when u pull the box with F consider the torques on the box. one will be due to F and other due to gravity, mg. the box will rotate if the torque due to F is higher. so the limiting value of F can be found by equating the torques. now with that value of F consider the friction, it should not have a maximum value which is greater than F. in that condition the box will slide.
for rolling or tippng F x L must be greater than mg x l/2.
 

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