Finding the Composition of Relations

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The discussion revolves around finding the composition of the inverse relations R^-1 and S^-1. The inverses are identified as R^-1 = { (2,1), (5,3), (2,2), (5,2) } and S^-1 = { (1,2), (3,5), (1,5), (5,5) }. The composition R^-1 o S^-1 is determined to map 1 to both 1 and 2, resulting in pairs (1,1) and (1,2). Participants express confusion regarding the necessity of additional sets typically included in their definitions, specifically the domain and range of the relations. The conversation highlights the importance of understanding the composition of relations even when not all sets are explicitly defined.
1MileCrash
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Homework Statement



R = { (1,2), (3,5), (2,2), (2,5) }
S = { (2,1), (5,3), (5,1), (5,5) }

Explicitly find the relation R^-1 o S^-1

Homework Equations





The Attempt at a Solution



This was on my test.

First I just wrote down the inverses:

R^-1 = { (2,1), (5,3), (2,2), (5,2) }
S^-1 = { (1,2), (3,5), (1,5), (5,5) }

I didn't know what to do because the definition we learned defines 3 other sets, and all of the exercises in my test book has those 3 other sets defined.

For example, there are usually sets A, B, and C along with the sets R and S. So I have no idea how I can apply the definition to do this.
 
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1MileCrash said:

Homework Statement



R = { (1,2), (3,5), (2,2), (2,5) }
S = { (2,1), (5,3), (5,1), (5,5) }

Explicitly find the relation R^-1 o S^-1

Homework Equations


The Attempt at a Solution



This was on my test.

First I just wrote down the inverses:

R^-1 = { (2,1), (5,3), (2,2), (5,2) }
S^-1 = { (1,2), (3,5), (1,5), (5,5) }
So S^{-1} "maps" 1 to 2 and R^{-1} maps 2 to 1. Therefore R^{-1}oS^{-1} maps 1 to 1 and contains the pair (1, 1).

R^{-1} also maps 2 to 2 so R^{-1}oS^{-1} also maps 1 to 2 and contains the pair (1, 2).

I didn't know what to do because the definition we learned defines 3 other sets, and all of the exercises in my test book has those 3 other sets defined.
What 3 sets?

For example, there are usually sets A, B, and C along with the sets R and S. So I have no idea how I can apply the definition to do this.
fog contains the pair (a, b) if and only if there exist some c such that g contains (a, c) and f contains (c, b).
 
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So (3,3) is in the composition because we have (5,3) and (3,5)?
 
1MileCrash said:
So (3,3) is in the composition because we have (5,3) and (3,5)?
(3, 3) is in \displaystyle R^{-1}\circ S^{-1} because, (3, 5) is in S^{-1} and (5, 3) is in R^{-1}\ .
 
I think the other three sets in my definition are A, B, and C and are dupposed to be the domain of R, the Range of R/domain of S, and the range of S.

Sound reasonable?
 
1MileCrash said:
I think the other three sets in my definition are A, B, and C and are supposed to be the domain of R, the Range of R/domain of S, and the range of S.

Sound reasonable?
As Halls said earlier, "What 3 sets?"

The domain of R is {1,2,3}.

The domain of S is {2,5}.

etc.
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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