Finding the Constant c for a Limit Problem

Click For Summary
SUMMARY

The discussion focuses on determining the constant c in the limit problem defined as Lim (x->3) (x^2 + x + c) / (x^2 - 5x + 6). The denominator factors to (x - 3)(x - 2), indicating that as x approaches 3, the denominator approaches zero. For the limit to exist, the numerator must also approach zero, leading to the condition that (x - 3) must be a factor of (x^2 + x + c). By equating coefficients, it is established that c must equal -3a, where a is derived from the factorization of the numerator.

PREREQUISITES
  • Understanding of limits in calculus
  • Ability to factor polynomials
  • Familiarity with the concept of continuity
  • Knowledge of algebraic manipulation
NEXT STEPS
  • Study the properties of limits in calculus
  • Practice polynomial factorization techniques
  • Explore the concept of removable discontinuities
  • Learn about the application of L'Hôpital's Rule
USEFUL FOR

Students studying calculus, particularly those focusing on limits and continuity, as well as educators seeking to reinforce these concepts in their teaching.

Kuma
Messages
129
Reaction score
0
limits problem solving help!

Alrighty so i have no idea where to even start...

Find the constant c such that

Lim
x-> 3

x^2+x+c
-----------
X^2 - 5x + 6


exists

Yeah so

so far i got as far as factoring the bottom

(x-3)(x-2)

And now i have no idea where to go from there
any ideas?
 
Physics news on Phys.org


As x-->3, the denominator tends to zero, so for the limit to have the slightest chance to exist, the numerator must approach zero as well. For which value of c does it do so?
 


require
(x-3)|(x^2+x+c)
that is find and "a" such that
(x-3)(x+a)=(x^2+x+c)
then set c=-3a
 

Similar threads

  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 22 ·
Replies
22
Views
2K
  • · Replies 7 ·
Replies
7
Views
1K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 5 ·
Replies
5
Views
1K
Replies
5
Views
3K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 6 ·
Replies
6
Views
1K
Replies
7
Views
2K