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question is...can we transform every thing to cylinderical and then use the formula for cartesian?I mean writing basis vectors of cartesian in terms of r and theta and z and basis vectors of cylindrical , and then write the x y z components of the vector(which we want its curl) in terms of its r and theta and z (cylindrical) components and then write the partial differentiations of cartesian in terms of cylindrical r and theta and then write the equation in cartesian>>transform everything to cylindrical>>get the desired formula!

I did this but it gave me wrong answer.WHY??!

I can and did derive the curl in different coordinates by using their definition but using the way I said above it should work...why not?