(adsbygoogle = window.adsbygoogle || []).push({}); URGENT: Finding the Current and Power across each Resistor in a Complicated Network

1. The problem statement, all variables and given/known data

For the circuit below, a 12 V batter is connected across the points a and b. Determine the following:

a) the equivalent resistance between points a and b

b) the total current flowing through the resistor network

c) the total power dissipated by the resistor network

d) the current through each individual resistor and the power dissipated by each resistor. Sum up the power dissipation from each and compare that sum to your result from c. Is this what you expect?

2. Relevant equations

series: Req=R1+R2+...

parallel: 1/Req=1/R1+1/R2+.....

I=V/R

P=I^2R

3. The attempt at a solution

a) I know how to do this part. I get 6 ohms.

b) using I=V/R=12/6=2A

c) P=I^2R=2^2*6=24 Watts

d) I have no idea how to do this part. How does the Voltage split up? Does 6V go into the top part then the 6 splits in to 3 for each part within the part? Then combine to form 6 again once it comes out the square in the top part?

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# Homework Help: : Finding the Current and Power across each Resistor in a Complicated Network

**Physics Forums | Science Articles, Homework Help, Discussion**