Find Ampermeter Current from Circuit | R1 = 10 Ω; R2 = 10 Ω; R3 = 30 Ω

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The discussion focuses on determining the current measured by an ammeter in a circuit with resistors R1, R2, and R3. The user attempts to apply Kirchhoff's rules to find the currents, concluding that I3 equals 1.14A. However, there is confusion regarding the voltage between points C and D, as it is not specified in the problem. A participant clarifies that since there is no connection at C and D, I2 must equal 0, which affects the calculations for I1 and I3. The conversation emphasizes the importance of understanding circuit connections to accurately apply Kirchhoff's laws.
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Homework Statement


There is a circuit which is shown in the picture. ##R_1=10 Ω;## ##R_2=10 Ω;## ##R_3=30 Ω##.
I need to find what ampermeter is showing.
123.png


Homework Equations


U=IR

The Attempt at a Solution


1234.png

I am trying to use kirchhoff rules here.

##I_1=I_2+I_3##
##I_1R_1+I_3R_3=80##
##I_2R_2=I_3R_3##

I get that ##I_3=1.14A##. Is this correct?
 
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Assuming C & D are open as shown, I2 should be 0.
 
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But how do I know whether there is voltage between C and D? It is not stated in the problem. In fact, the next question of this problem asks to find the voltage between C & D.
 
There will be a voltage between C and D, even though I2 = 0.
 
kaspis245 said:
I am trying to use kirchhoff rules here.
snip
I2R2=I3R3

That last line isn't correct. The voltage across R2 and R3 are not the same.

There is nothing connected to C and D so no current flows into or out of C and D. So I2 = 0. Think what that means for I1 and I3.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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