Finding the Derivative of a Square Root Function

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SUMMARY

The discussion focuses on finding the derivative of the square root function f(x) = x^(1/2) using the limit definition of a derivative. The user initially set up the difference quotient as [(x+h)^(1/2) - x^(1/2)]/h but was unsure how to simplify it. The solution provided involved rationalizing the numerator to facilitate simplification, leading to a clearer path to the derivative.

PREREQUISITES
  • Understanding of basic calculus concepts, specifically derivatives.
  • Familiarity with the limit definition of a derivative.
  • Knowledge of algebraic manipulation techniques, including rationalization.
  • Experience with functions and their properties, particularly power functions.
NEXT STEPS
  • Study the limit definition of derivatives in depth.
  • Learn how to rationalize both numerators and denominators in algebraic expressions.
  • Explore the rules of differentiation for power functions and their applications.
  • Practice finding derivatives of various functions using different methods, including the quotient rule and chain rule.
USEFUL FOR

Students learning calculus, educators teaching derivative concepts, and anyone seeking to strengthen their understanding of differentiation techniques.

gomes.
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function --- derivative (help!)

Homework Statement




[PLAIN]http://img15.imageshack.us/img15/705/123gm.jpg

but instead of f(x)=x^-2, let f(x) = x^(1/2 )


The Attempt at a Solution




So, I did

[ (x+h)^1/2 - (x)^1/2 ]/ h

But I am not sure how to simplify it. What would be my next step? Thanks a lot :)
 
Last edited by a moderator:
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gomes. said:

Homework Statement




[PLAIN]http://img15.imageshack.us/img15/705/123gm.jpg

but instead of f(x)=x^-2, let f(x) = x^(1/2 )


The Attempt at a Solution




So, I did

[ (x+h)^1/2 - (x)^1/2 ]/ h

But I am not sure how to simplify it. What would be my next step? Thanks a lot :)

Rationalize the numerator. (Like rationalizing the denominator, only opposite) :cool:
 
Last edited by a moderator:


Ah okay, yea I got it now. thanks :)
 

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