Finding the direction of an angle in the unit circle

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SUMMARY

This discussion focuses on determining the direction of a vector in the unit circle using its x and y components. When both components are negative, the vector lies in the third quadrant, requiring the addition of 180 degrees to the inverse tangent output. For vectors in the second quadrant, 180 degrees is also added to the negative output from the inverse tangent function, while for the fourth quadrant, the output can be expressed as a negative angle or converted to a positive angle by adding 360 degrees. It is essential to include directional phrases such as "counterclockwise from the positive x axis" for clarity.

PREREQUISITES
  • Understanding of inverse tangent functions
  • Knowledge of vector components in Cartesian coordinates
  • Familiarity with the unit circle and quadrants
  • Basic trigonometric concepts and angle measurement
NEXT STEPS
  • Learn how to use polar coordinate features on calculators for vector direction
  • Study the properties of inverse trigonometric functions in detail
  • Explore vector representation and analysis in physics
  • Investigate graphical methods for visualizing vector directions
USEFUL FOR

Students studying trigonometry, physics enthusiasts, and anyone seeking to understand vector direction in the context of the unit circle.

aron silvester

Homework Statement


I'm having trouble understanding how to find the angle of a vector. Here we are given the x and y component to help us find the direction of vector C. In this case, both x and y component is negative, so it should be in the third quadrant. I know that since we have both the x and y component, we need to use inverse tangent, and since the vector is in the third quadrant we add 180 to the inverse tangent as shown in part 3 because the vector is past 180, but before 270. My question is if the vector is in the second quadrant, would we add 90 to inverse tangent? If the vector is in the fourth quadrant, would we add 270 to inverse tangent? This is seriously frustrating me.

Homework Equations


It's all in part 3.

The Attempt at a Solution


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Most calculators give only the "principal value" of the inverse tangent function. https://en.wikipedia.org/wiki/Inverse_trigonometric_functions#Principal_values

For the first quadrant you are OK.

For the fourth quadrant, you are also OK. Your calculator should give a negative answer, such as -30o. This is interpreted to mean that the vector is pointing 30o below the positive x axis. If you want, you can express the angle as 360o - 30o = 330o counterclockwise from the + x axis.

For the second and third quadrants you add 180o to the calculator's output. The result is then the angle as measured counterclockwise from the positive x axis.

So, if the vector is in the second quadrant, your calculator would give a negative value, say -40o. Adding 180o to this gives 140o. So, the direction of the vector is 140o counterclockwise from the positive x axis.

-----------------------------------------

Another approach is to always take the absolute value of the output of the calculator and express the direction as "above the positive x axis", "above the negative x axis", "below the negative x axis", or "below the positive x axis" depending on being in the first, second, third, or fourth quadrant, respectively. You can always tell which quadrant by inspecting the signs of the x and y components of the vector.

In any case, avoid expressing the direction of a vector with just an angle. Always include an explanatory phrase such as "counterclockwise from the positive x axis" or "above the negative x axis", etc. Or, include a diagram showing the direction of the vector with the angle indicated on the diagram.

Note: Some calculators have polar coordinate features which will always give you the answer as measured counterclockwise from the positive x-axis so that you don't need to do anything extra, no matter which quadrant. All you need to do is input the x and y components of the vector, including sign. You don't need to use the inverse tangent function. For an example, see


Of course details will vary with the brand of the calculator.
 
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TSny said:
Most calculators give only the "principal value" of the inverse tangent function. https://en.wikipedia.org/wiki/Inverse_trigonometric_functions#Principal_values

For the first quadrant you are OK.

For the fourth quadrant, you are also OK. Your calculator should give a negative answer, such as -30o. This is interpreted to mean that the vector is pointing 30o below the positive x axis. If you want, you can express the angle as 360o - 30o = 330o counterclockwise from the + x axis.

For the second and third quadrants you add 180o to the calculator's output. The result is then the angle as measured counterclockwise from the positive x axis.

So, if the vector is in the second quadrant, your calculator would give a negative value, say -40o. Adding 180o to this gives 140o. So, the direction of the vector is 140o counterclockwise from the positive x axis.

-----------------------------------------

Another approach is to always take the absolute value of the output of the calculator and express the direction as "above the positive x axis", "above the negative x axis", "below the negative x axis", or "below the positive x axis" depending on being in the first, second, third, or fourth quadrant, respectively. You can always tell which quadrant by inspecting the signs of the x and y components of the vector.

In any case, avoid expressing the direction of a vector with just an angle. Always include an explanatory phrase such as "counterclockwise from the positive x axis" or "above the negative x axis", etc. Or, include a diagram showing the direction of the vector with the angle indicated on the diagram.

Note: Some calculators have polar coordinate features which will always give you the answer as measured counterclockwise from the positive x-axis so that you don't need to do anything extra, no matter which quadrant. All you need to do is input the x and y components of the vector, including sign. You don't need to use the inverse tangent function. For an example, see


Of course details will vary with the brand of the calculator.

Thanks!
 
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