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Finding the direction on a second displacement

  1. Sep 21, 2007 #1
    1. The problem statement, all variables and given/known data

    A man pushing a mop across a floor causes it to undergo two displacements. The first has a magnitude of 150 cm and makes an angle of 130° with the positive x axis. The resultant displacement has a magnitude of 136 cm and is directed at an angle of 40.0° to the positive x axis. Find the magnitude and direction of the second displacement.

    3. The attempt at a solution

    I was able to figure out the magnitude through trial and error. I thought because it says to find the second displacement, and not the resultant displacement that Pythagoreans formula would not work, but it did. sqrt(150^2+136^2) gave me 202.5cm and the online homework accepted it as the right answer.

    Because it did accept it as the right answer, I'm very confused. I thought the resultant displacement was the net displacement of one and two (the hypotenuse), but since the Pythagorean formula worked, I can't visualize what the displacements should look like in my head. I tried creating an arbitrary triangle and setting opposite equal to 130 and adjacent to 150 and then using arctan to find the angle, but it came back as incorrect. Now I have no idea how to find the direction of the 202.5 magnitude displacement.

    Please help! I refuse to stop for the night until I figure this problem out.
     
  2. jcsd
  3. Sep 21, 2007 #2

    learningphysics

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    First draw a picture... you should know what the vectors look like...

    Did you draw the original vector... and the resultant vector?
     
  4. Sep 21, 2007 #3
    I tried to draw a picture, but the problem description is really throwing me off. Also, I don't have a protractor.

    But even with a picture, I don't know how to find the angle.
     
  5. Sep 21, 2007 #4

    learningphysics

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    Yes, but you need the picture correctly, so that you know which angle to find...

    You don't need a protractor... just sketch it with north south east west axes... Draw the two vectors given in the problem at 130 degrees and 40 degrees...
     
  6. Sep 21, 2007 #5
    Here is what is throwing me off, we have learned to draw the vectors in class, starting with 1, and drawing the next vector off the first vectors tail. But as I understand the problem, it gives the first vector, and the resultant vector. So do they both originate from the same point?
     
  7. Sep 21, 2007 #6

    learningphysics

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    If you draw the two vectors from the same point... then suppose you draw a vector, from where the original vector ends... to where the resultant ends... (ie the arrowhead of the original vector... to the arrowhead of the resultant)

    Do you agree that the original vector plus this new vector... add to the resultant vector? So this new vector is the vector you need.

    If you find this approach confusing... here's another way to go about it...

    you have two vectors that add to the resultant: [tex]\vec{a} + \vec{b} = \vec{r}[/tex]

    You are given a and r... you need to find b. So solve for b in the equation:

    [tex]\vec{b} = \vec{r} - \vec{a}[/tex]

    or in other words:

    [tex]\vec{b} = \vec{r} + (-\vec{a})[/tex]

    So drawing [tex]\vec{r}[/tex]... and adding to it [tex]-\vec{a}[/tex] will also give you the result.
     
  8. Sep 21, 2007 #7
    Ok, I have the picture, that makes sense now. Forgive me for being dense, but I still can't see how this helps me find the direction (angle) of the second vector in relation to the x-axis.
     
  9. Sep 21, 2007 #8

    learningphysics

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    You can calculate that angle... Have a look at this sketch:

    http://www.imagevimage.com/gallery.php?entry=images/angle.gif

    Does the picture make sense? can you find angle x?
     
  10. Sep 21, 2007 #9
    I can't figure out how to find values for two sides of the triangle it creates, so I can't find the angle. Is there another way I am unaware of?
     
  11. Sep 21, 2007 #10

    learningphysics

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    What is the angle with the 2 squiggly lines...
     
  12. Jan 25, 2008 #11
    Hi.
    I need some help with physics/motion and i wasn't sure where to post.
    This was the first thing i saw when i used google.
    I am having a really really hard time understanding motion and where to plug things into/ what the formulas are.
    I would really appreciate some help if anyone could.
    Also please try not to think i'm an idiot i am just learning all of this.
    1) What is the formula for resultant displacement *lost my notes :(
    2) If the formula is(for resultant displacement) dr= d1+d2 then where do i plug in the directions like north and south
    The question is:
    A soccer player leaves the bench and runs 35m[N] and then 25m. Find the resultant displacement.
     
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