Finding the Domain of the Bessel Function Series

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Homework Help Overview

The discussion revolves around finding the domain of the series \(\sum_{n= 0}^\infty \frac{(-1)^{n}x^{2n}}{2^{2n}(n!)^{2}}\), which relates to Bessel functions. Participants are exploring the simplification of terms within the series and the implications for determining the domain.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the simplification of terms involving factorials and powers of two. Questions arise about the application of the law of exponents and the relationship between \(n!\) and \((n+1)!\). There is also a mention of polynomial division in relation to the series.

Discussion Status

The discussion is ongoing, with participants providing guidance on simplifying expressions and questioning each other's reasoning. Some participants are attempting to clarify their understanding of the simplification process, while others are exploring different interpretations of the series.

Contextual Notes

There seems to be confusion regarding the simplification steps and the notation used, which may be affecting the clarity of the discussion. Participants are also referencing a simpler series to illustrate their points, indicating a need for foundational understanding.

Stratosphere
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Homework Statement


Find domain of [tex]\sum_{n= 0}^\infty \frac{(-1)^{n}x^{2n}}{2^{2n}(n!)^{2}}[/tex]


Homework Equations




The Attempt at a Solution


I set it all up but I can't really seem to simplify it.

[tex]\frac{(-1)^{n+1}x^{2(n+1)}}{2^{2n+2}(n+1)!^{2}}\bullet\frac{2^{2n}(n!)^{2}}{(-1)^{n}x^{2n}}[/tex]
 
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Why can't you simplify it? What's 2^(2n)/(2^(2n+2))? What's n!/(n+1)!?
 
You mean polynomial division?
 
Stratosphere said:
You mean polynomial division?

No, I mean the law of exponents for the first one and realizing (n)!/(n+1)!=(1*2*3*...*n)/(1*2*3*...*n*(n+1)) for the second one.
 
Explain what the mean by showing me on this much simpler one.

[tex]\sum_{n= 0}^\infty n!x^{n}[/tex]

Setting it up I get [tex]\frac{(1+n!)x^{n+1}}{n!x^{n}}[/tex]

Do I cross out the factors?
 
You meant to write (1+n)!, I hope, not (1+n!). Yes, you just cancel the common factors in the numerator and denominator. What do you get?
 
So, I got x+1 but I must have messed something up.
 
Stratosphere said:
So, I got x+1 but I must have messed something up.

Apparently, but not showing how you got that doesn't make it easy to help. What are x^(n+1)/x^n and (n+1)!/n!?
 

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