Finding the efficiency of an engine given energy input, energy wasted.

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SUMMARY

The discussion centers on evaluating the efficiency of an engine that claims to convert 1.1x108 J of heat energy at 400K while rejecting 5.0x107 J at 200K. The calculated efficiency (η) is 54%, derived using the formula η = 1 - (Q2/Q1). However, the realistic efficiency is estimated to be around 30% or less, indicating that the project is not advisable for investment. The relevance of temperature and the Carnot efficiency limit is also highlighted as critical factors in this evaluation.

PREREQUISITES
  • Understanding of thermodynamics principles, specifically heat engines
  • Familiarity with the Carnot efficiency limit
  • Knowledge of efficiency calculations using the formulas W = Q1 – Q2 and η = W/Q1
  • Basic grasp of entropy and its implications in thermodynamic systems
NEXT STEPS
  • Research the Carnot efficiency limit and its application in evaluating engine performance
  • Study the concept of net entropy change in thermodynamic systems
  • Learn about different types of heat engines and their efficiencies
  • Explore advanced thermodynamic equations and their practical applications in engineering
USEFUL FOR

Engineers, thermodynamics students, and investors evaluating the feasibility of energy projects will benefit from this discussion.

Dez1
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Homework Statement


An inventor claims to have developed an engine which takes in 1.1x108J of heat energy at 400K, and rejects 5.0x107J of heat energy at 200K. Would you advise investing in this project? Explain your answer.


Homework Equations


W = Q1 – Q2
η = W/Q1 = 1 – Q2/Q1


The Attempt at a Solution


η=1-(Q2/Q1)
=1-(5*10^7/1.1*108)
=0.54

Which means the inventor is claiming 54% efficiency. In reality such an engine would be in the region of 30% efficiency or less.Therefore I would not suggest investing in this project."

I think my answer seems too short, which means I'm probably doing it wrong. Also, the temperatures probably have some relevance to the solution so I'm probably using the wrong equation(s).
 
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Dez1 said:

Homework Statement


An inventor claims to have developed an engine which takes in 1.1x108J of heat energy at 400K, and rejects 5.0x107J of heat energy at 200K. Would you advise investing in this project? Explain your answer.


Homework Equations


W = Q1 – Q2
η = W/Q1 = 1 – Q2/Q1


The Attempt at a Solution


η=1-(Q2/Q1)
=1-(5*10^7/1.1*108)
=0.54

Which means the inventor is claiming 54% efficiency. In reality such an engine would be in the region of 30% efficiency or less.Therefore I would not suggest investing in this project."

I think my answer seems too short, which means I'm probably doing it wrong. Also, the temperatures probably have some relevance to the solution so I'm probably using the wrong equation(s).

Or simply consider the net entropy change of the system.
 

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