Finding the electric field at a point midway between two charges

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SUMMARY

The electric field at a point midway between two charges of +30.0 x 10^-9 C and +60.0 x 10^-9 C, separated by 30.0 cm, is calculated using the formula E = Kq / r^2. The correct distance from each charge to the midpoint is 0.15 m, not 0.30 m. The individual electric fields are 12,000 N/C directed toward the +30.0 x 10^-9 C charge when considering vector direction, resulting in a total electric field of 12.0 x 10^3 N/C.

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Bryster77
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Find the electric field at a point midway between the two charges of +30.0 x 10^-9 C and +60.0 x 10^-9 C separated by a distance of 30.0cm


My work:

E= Kq / r^2

E= (9 x 10^9 NxM^2/C^2)(30.0 x 10^-9 C)/ (0.30m)^2

i get 3000 N/C

E= (9x10^9 NxM^2/C^2)(60 x 10^-9 C)/(0.30m)^2

i get 6000 N/C

i added the two together and got 9000N/C, but its telling me the answer is "12.0 x 10^3N/C toward 30 nC"

i am confused on what i am doing wrong. please help
 
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I believe your r value is wrong. The distance from a charge to the midpoint is NOT 0.30m. 0.30m is the distance from one charge to the other. Also, electric field is a vector quantity, so directions matter when you sum up contributions from multiple sources.
 
I completely understand it now, thank you. =D
 
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