Finding the electric flux through a sphere

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SUMMARY

The electric flux through a sphere placed in a uniform electric field of E=233 N/C is zero, as established by Gauss's Law. The discussion highlights the importance of considering the dot product in the calculation of electric flux, specifically the component of the electric field in the direction of the surface area. The integral for electric flux simplifies to E*(4πR), but since there is no net charge within the sphere, the total flux remains zero. This conclusion is supported by the principle that any electric field entering the sphere must also exit it.

PREREQUISITES
  • Understanding of Gauss's Law
  • Familiarity with electric fields and flux calculations
  • Knowledge of vector dot products
  • Basic concepts of surface area in three-dimensional geometry
NEXT STEPS
  • Study the application of Gauss's Law in various geometries
  • Learn about electric field lines and their properties
  • Explore vector calculus, focusing on dot products and their significance
  • Investigate the implications of electric flux in different physical scenarios
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Students in physics, particularly those studying electromagnetism, educators teaching electric field concepts, and anyone interested in understanding the principles of electric flux and Gauss's Law.

Timebomb3750
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Homework Statement


A sphere of radius R is placed in a uniform electric field of E=233 N/C i. Find the electric flux into and out of the sphere.


Homework Equations


I understand that Gauss's Law is shown as...
∫E dot dA = Q/epsilon not


The Attempt at a Solution



Well, since we're dealing with a sphere with E being constant, I figured you could pull the E out of the integral and be left with E∫dA where dA is =4pi*r^2. So you'd be left with E(4pi*R). But this doesn't look right to me. Keep in mind, there is no charge in or out of the sphere. And the field lines are perfectly horizontal through the sphere.
 
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Timebomb3750 said:
Well, since we're dealing with a sphere with E being constant, I figured you could pull the E out of the integral and be left with E∫dA where dA is =4pi*r^2. So you'd be left with E(4pi*R).
You forgot about the dot product. You need the component of surface area in the direction of the field. (Or vice versa.)
 
I'm confused about what you're asking for. Are you saying there should be a dot somewhere in my flux=E(4pi*R) equation. I understand what the dot product is (I use it a lot in my Calc 3 class) I'm confused as to what you mean by "the component of the surface area". I understand that the field lines only have an x-component or i, so they're horizontal through the sphere.
 
What do you think E*dA means? What's the significance of the dot product?

(You were treating E*dA as if it were the same as EdA.)
 
Doc Al said:
What do you think E*dA means? What's the significance of the dot product?

(You were treating E*dA as if it were the same as EdA.)

Oops. I see. So, I should be left with E*(4piR) R=radius. But what I'm now stumped on is the component of the surface area. As I said before. I understand the E has an i-component. But how do I find the components of the surface area?
 
Well, you can do it the hard way. (By setting up the integral.) Or you can think about it a bit and maybe it'll dawn on you. Imagine a hemisphere with its axis along the x-axis. What will be the x-component of its surface area?

This might be an even better way to visualize it. What flux of E field will be intercepted by the sphere? (Who cares about the shape of the surface?)
 
Wouldn't the total flux through the hemisphere be zero? Thus, meaning the flux through a sphere would be zero as well? I'm talking about total flux meaning the sum of the positive and negative flux.
 
Timebomb3750 said:
Wouldn't the total flux through the hemisphere be zero? Thus, meaning the flux through a sphere would be zero as well? I'm talking about total flux meaning the sum of the positive and negative flux.
The total flux through the sphere will be zero*. (Since whatever goes into it must go out of it.) But not through the hemisphere.

*That should be clear from Gauss's law.
 

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