Finding the Electric Potential at a Point Due to Multiple Charges

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SUMMARY

The discussion focuses on calculating the electric potential at the origin due to multiple point charges. Specifically, a charge of +21.9 micro-Coulombs at (-3.3 m, 0 m), a charge of -8.5 micro-Coulombs at (0 m, +3.8 m), and a charge of +15.6 micro-Coulombs at (+3.3 m, +3.8 m) contribute to the potential. The final calculated electric potential at the origin, with a charge of -15.4 micro-Coulombs, is determined to be -1.04 Joules. The formula used includes the constant k (8.99 x 10^9 Nm²/C²) and the distances from each charge to the origin.

PREREQUISITES
  • Understanding of electric potential and its calculation
  • Familiarity with Coulomb's law and point charges
  • Knowledge of vector magnitude and distance calculation in a Cartesian coordinate system
  • Proficiency in using the formula for potential energy change, ΔU = Uf - Ui
NEXT STEPS
  • Study the concept of electric potential due to multiple point charges
  • Learn how to calculate distances between points in a Cartesian coordinate system
  • Explore the implications of negative and positive charges on electric potential
  • Investigate the use of simulation tools for visualizing electric fields and potentials
USEFUL FOR

This discussion is beneficial for physics students, educators, and anyone interested in electrostatics and electric potential calculations in multi-charge systems.

eestep
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Homework Statement


A charge of +21.9 micro-Coulombs is placed at x=-3.3 m, y=0 m, a charge of -8.5 micro-Coulombs is placed at x=0 m, y=+3.8 m, and a charge of +15.6 micro-Coulombs is placed at x=+3.3 m, y=+3.8 m. If a charge of -15.4 micro-Coulombs is placed at origin, what is electrical potential of this charge in Joules? Answer is -1.04.


Homework Equations


[tex]\Delta[/tex]U=Uf-Ui


The Attempt at a Solution


Vo=k(q1/r1+q2/r2+q3/r3)=(8.99 x 109Nm2/C2)(21.9 x 10-6C/3.3m+-8.5 x 10-6C/3.8m+15.6 x 10-6C/7.1m)=5.93 x 104V
Uf=q4Vo
q4Vo-0=(-15.4 x 10-6C)(5.93 x 104V)
 
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hi eesteeestep! :wink:
eestep said:
… and a charge of +15.6 micro-Coulombs is placed at x=+3.3 m, y=+3.8 m

… =(8.99 x 109Nm2/C2)(… +15.6 x 10-6C/7.1m)

no, you've added 3.8 to 3.3 to get 7.1 :frown:

(3.3,3.8) is a vector

its magnitude is … ? :smile:
 

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