Finding the energy dissipated per cycle in a Stirling Engine

[TheBigDig]

1.Recently, we performed an experiment to measure the efficiency of the Stirling Engine. The experimental method can be seen in the image provided. We have been asked to calculate the power dissipation P^R and the energy dissipation per cycle W_R as part of our lab report. The other variables mentioned are R (the resistance), U_R (the measured voltage), n (the revolutions per min), T₁ and T₂, the temperature of two thermocouples connected to the engine.
At R = 500Ω, the recorded values are: U_R = -3.68V, n = 494 cycles min^-1, T₁ = 150°C and T₂ = 63.2°C.2.

• P_R = V²/R
• W = P*t (where W is work, P is power and t is time)

3. I was able to calculate the Power Dissipation using the above equation (P_R = 0.027 W) but I'm totally lost on finding W_R. I've tried using the above equation and subbing in W_R and P_R and finding the time it takes for 1 cycle but that gives me a very small number when compared to the value of W_pV = -2.4498J.

 

[Simon Bridge]

If you know the energy dissipated per second, then it is a matter of knowing how many cycles per second and converting.
If there are a lot of cycles per second, then the resulting energy per cycle will be very small.