- #1
fireb
- 11
- 0
Homework Statement
The plane that passes through the line of intersection of the plane x-z=1 and y+2z=3 and is perpendicular to the plane x+y-2z=1
Homework Equations
The Attempt at a Solution
I found the intersection point of the 2 planes by setting z=0 yielding the point (1,3,0). Next I found the normal of the 2 planes that is intersecting, (1,0,-1)x(0,1,2)= (1,-2,1). the normal of the perpendicular plane is (1,1,-2). since the 2 normal are not parallel, i found another normal (1,-2,1) x (1,1,-2) which yields(3,3,3). Then substituting the point (1,3,0) and (3,3,3) into the plane equation. So 3(x-1)+3(y-3)+3z=d
I am unsure if this is the correct answer or this is how you do it? It would be nice if someone would confirm this with me or lead me to the right direction on how to solve this.
Thanks in advance