Finding the equation of state and internal energy of a given gas.

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SUMMARY

The discussion focuses on deriving the equation of state and internal energy for a gas composed of N distinguishable particles with zero rest mass. The relationship between energy E and momentum p is defined as E = pc, and the number of single-particle energy states is given by 4πVp²dp. The partition function Z(E) is obtained by integrating 4πVp²dp, leading to the equation of state expressed as (∂S/∂V)₍ₙ,ₑ₎ = P/T and the internal energy defined by (∂/∂E)₍ₙ,ₕ₎ = 1/T. A correction was made regarding the second equation, confirming that (∂S/∂E)₍ₙ,ₕ₎ = 1/T is accurate.

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  • Knowledge of thermodynamic equations of state
  • Basic calculus for integration and differentiation
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quantumkiko
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Consider a gas contained in volume V at temperature T. The gas is composed of N distinguishable particles at zero rest mass, so that the energy E and momentum p are related by E = pc. The number of single-particle energy states in the range p to p + dp is 4\pi Vp^2 dp. Find the equation of state and the internal energy of the gas and compare with an ordinary (ideal?) gas.

In how I understand the problem, you must integrate 4\pi Vp^2 dp and E = pc to get the partition function Z(E) then use the entropy S = k_b ln Z to get the equation of state given by

\left(\frac{\partial S}{\partial V}\right)_{N, E} = \frac{P}{T}

and the internal energy by,

\left(\frac{\partial}{\partial E}\right)_{N, V} = \frac{1}{T}.

Did I understand the problem correctly?
 
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You mean

\left(\frac{\partial S}{\partial E}\right)_{N, V} = \frac{1}{T}

for the second equation? Looks good.
 
Yes you're right. Sorry for the mistake. And what I meant was you must integrate 4\pi Vp^2 dp and use E = pc to express the integral in terms of E instead of p. Thank you, I hope I got it correct then. What would be the bounds of the integral?
 

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