Finding the expected value of a probability function

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SUMMARY

The discussion focuses on calculating the expected value E(X) of a random variable X with the probability function f(x) = 0.49x(0.3)^(x-1). The correct formula for E(X) is established as E(X) = sum of all x of x*f(x), which simplifies to E(X) = 0.49 * sum of all x of x^2(0.3)^(x-1). However, concerns are raised regarding the convergence of the probability function across the entire real line, indicating potential issues with its validity.

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Jessica21
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1. Suppose X is a random variable with probability function
f(x) = 0.49x(0.3)^ (x-1). Find E(x).




2. E(X) = sum of all x of x*f(x)



3. so I know that E(X) = sum of all x of x*f(x)
so E(x)= 0.49* sum of all x of x^2(0.3)^(x-1)

But I'm not sure how do i evaluate the sum?
Can anyone please help me,thanks!
 
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Are you sure you have the right probability function? This one doesn't converge on the entire real line and I wasn't able to find an interval where it integrated to 1.

In any event, if you have a random variable X with a probability density function f(x), then the expected value of X is
[tex]\intop_{-\infty}^{\infty} xf(x) dx[/tex]
 

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