- #1
Jessica21
- 5
- 0
1. Suppose X is a random variable with probability function
f(x) = 0.49x(0.3)^ (x-1). Find E(x).
2. E(X) = sum of all x of x*f(x)
3. so I know that E(X) = sum of all x of x*f(x)
so E(x)= 0.49* sum of all x of x^2(0.3)^(x-1)
But I'm not sure how do i evaluate the sum?
Can anyone please help me,thanks!
f(x) = 0.49x(0.3)^ (x-1). Find E(x).
2. E(X) = sum of all x of x*f(x)
3. so I know that E(X) = sum of all x of x*f(x)
so E(x)= 0.49* sum of all x of x^2(0.3)^(x-1)
But I'm not sure how do i evaluate the sum?
Can anyone please help me,thanks!