Finding the expression for a polarized light wave

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SUMMARY

The expression for a P-state lightwave propagating at 45 degrees in the xy-plane is derived as E = (-i + j) (√2/2) E_0 sin(k/√2 (x + y) - ωt). The amplitude E_0 is split into components E_0x and E_0y, calculated as E_0 cos(45) and E_0 sin(45), respectively. The wave function is confirmed to be a sine wave due to the initial conditions where the field is zero at t = 0, x = 0, and y = 0. A cosine wave would introduce a phase shift, resulting in a sine wave ultimately.

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Homework Statement



Find an expression for the P-state lightwave of angular frequency w and amplitude E_0 propagating along a line in the xy-plane at 45 degrees to the x-axis and having its plane of vibration corresponding to the xy-plane. At t = 0, y = 0, and x = 0 the field is 0.

Homework Equations



E_0x = E_0 cos(45)
E_0y = E_0 sin(45)

The Attempt at a Solution



I thought that it would be a sine wave given the initial conditions
Thus, E = (-i + j) sqrt(2)/2 E_0 sin(k/sqrt(2) (x + y) - wt)

where k = k(i + j)/sqrt(2)

Or is it going to be a cosine wave?
 
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You want a sine wave because sin(0) = 0. If you use a cosine then you will have a phase factor of Pi/2, which would give you a sine wave in the end.
 

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