Finding the horizontal shift of a function

AI Thread Summary
The discussion revolves around finding the horizontal shift of a function and the confusion surrounding the correct point used for calculations. Participants note that the original post incorrectly uses the point (0, 5) instead of the correct point (0, 4.586) for determining the value of C. This miscalculation leads to discrepancies in results when applying the inverse cosine function. The importance of accurate measurements and understanding the geometric context is emphasized, as it directly impacts the calculations. Ultimately, the consensus is that the author made a mistake in their approach.
Einstein44
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Homework Statement
I was trying to find the horizontal shift of the function, as shown in the picture attached below. It clearly states, that this was found through simultaneous eqn's, but I am unsure how this is done.
Relevant Equations
##y=1.5 cos(\frac{2\pi }{23}x+C)+5.4##
Screenshot 2021-12-22 at 15.24.40.png

I've never actually done this, so I was wondering if someone could show me how this is done. One way I tried was by simply using ##cos^{-1}## in order to cancel the cosine, but that gave me a different value, so I assume this is not how you are supposed to do this.

--> I know I am supposed to know this, but here I am... :)
 
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Yes, he plugged in the x,y values from (0,5) and used ##\cos^{-1}##.
I have no idea what the "From my measurements" line is talking about. It might have something about simultaneous equations, but I can't guess.
I also can't guess why the value of C is that particular solution. There may be some geometry involved that is not shown in your post.
 
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FactChecker said:
Yes, he plugged in the x,y values from (0,5) and used ##\cos^{-1}##.
I have no idea what the "From my measurements" line is talking about. It might have something about simultaneous equations, but I can't guess.
I also can't guess why the value of C is that particular solution. There may be some geometry involved that is not shown in your post.
Hmmm... This is the website, in case you want to have a look: https://www.ukessays.com/essays/mat...area-of-complex-three-dimensional-objects.php
I can't figure out what kind of geometry could have been used here, as it seems to be a pretty simple scenario to me (and no indication on the website whatsoever), but by calculating this using ##\cos^{-1}## gave me a different value... Have you tried calculating it?

Edit: I believe the "from my measurments" in this case refers to the measurments he took in order to find the rest of the function (a,b,d).
 
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The work on the website is all about the geometry of a vase. That probably determines which of the set of solutions for C are valid in that situation..
 
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Einstein44 said:
One way I tried was by simply using ##cos^{-1}## in order to cancel the cosine, but that gave me a different value, so I assume this is not how you are supposed to do this.
The closest thing I got to their answer was ##\arccos(-0.4/1.5)-2\pi = 1.8407291226283 - 2\pi = -4.44245618455128##, so I don't know what they did.
 
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FactChecker said:
The closest thing I got to their answer was ##\arccos(-0.4/1.5)-2\pi = 1.8407291226283 - 2\pi = -4.44245618455128##, so I don't know what they did.

No idea either!

1640238664046.png


?
 
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FactChecker said:
The closest thing I got to their answer was ##\arccos(-0.4/1.5)-2\pi = 1.8407291226283 - 2\pi = -4.44245618455128##, so I don't know what they did.
Alright, I guess this will remain a mystery. Thanks for the contribution.
 
The author has made a mistake. Simple as that!

In the Post #3 link, they say they are using the point (0, 5). But if you look carefully at the diagram
https://images.ukessays.com/180520/3/0651715.022.jpg
the correct point is clearly shown to be (0, 4.586), and this is in fact what has been used to calculate C (not (0,5)).

Easy to confirm: evaluate y using x=0 and the calculated value of C = -4.13893405 and we get:
##y = 1.5 cos(\frac{2\pi }{23}0-4.13893405)+5.4 = 4.5861937##
as required.
 
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Steve4Physics said:
The author has made a mistake. Simple as that!

In the Post #3 link, they say they are using the point (0, 5). But if you look carefully at the diagram
https://images.ukessays.com/180520/3/0651715.022.jpg
the correct point is clearly shown to be (0, 4.586), and this is in fact what has been used to calculate C (not (0,5)).

Easy to confirm: evaluate y using x=0 and the calculated value of C = -4.13893405 and we get:
##y = 1.5 cos(\frac{2\pi }{23}0-4.13893405)+5.4 = 4.5861937##
as required.
True, that makes sense.
 
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Steve4Physics said:
The author has made a mistake. Simple as that!

In the Post #3 link, they say they are using the point (0, 5). But if you look carefully at the diagram
https://images.ukessays.com/180520/3/0651715.022.jpg
the correct point is clearly shown to be (0, 4.586), and this is in fact what has been used to calculate C (not (0,5)).

Easy to confirm: evaluate y using x=0 and the calculated value of C = -4.13893405 and we get:
##y = 1.5 cos(\frac{2\pi }{23}0-4.13893405)+5.4 = 4.5861937##
as required.
I thought about that too. But the y-ordinate 4.586 is not a measured value. It came from using the (wrongly) calculated sine graph parameters!.
 
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neilparker62 said:
I thought about that too. But the y-ordinate 4.586 is not a measured value. It came from using the (wrongly) calculated sine graph parameters!.
Aha, you are right! I rushed in without reading the text carefully. Apologies to all. But let me try to redeem myself...

In the text of the Post #3 link
https://www.ukessays.com/essays/mat...area-of-complex-three-dimensional-objects.php
the author says:
“This means that either the point of the base (25, 4.05) or the top point (0, 5) [must be used to find C]”.

In fact the author has used the point (25, 4.05), not (0, 5) to calculate C.

##C = cos^{-1}(\frac{(y-5.4)}{1.5}) - \frac{2π}{23}x##

##=cos^{-1}(\frac{(4.05-5.4)}{1.5}) - \frac{2π}{23}25 = -4.1389834##
 
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