- #1

newtomath

- 37

- 0

[ 4* (x^3/y^2) + (3/y)] dx + [3*(x/y^2) +4y]dy=0

I found My= -8x^3y^-3 - 3y^-2 and Nx= 3y^-2

i then subtracted Nx from My and divided by [3*(x/y^2) +4y]

[-8x^3y^-3 - 6y^-2] / [3*(x/y^2) +4y]. can you guys give me a hint as to where my error is?