Finding the intersection of subspaces, and addition of subspaces

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Homework Help Overview

The discussion revolves around finding the intersection and addition of subspaces defined by linear combinations of vectors in R^4. Specifically, the original poster presents a problem involving the subspaces E = span{u, 2v} and F = span{w, v}, where {u, v, w} is a linearly independent set of vectors.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore the meaning of spans and linear combinations, questioning whether span{u, 2v} contains span{u, v}. There is discussion about the implications of linear independence and how to find the intersection of the two subspaces given that w is not equal to u.

Discussion Status

Some participants have offered insights into the nature of spans and linear combinations, while others are questioning the definitions and relationships between the subspaces. There is an ongoing exploration of how to approach the intersection and addition of these subspaces without reaching a consensus.

Contextual Notes

Participants are considering the implications of linear independence and the specific vectors involved, as well as the geometric interpretation of spans. There is a noted uncertainty about the relationship between the spans and how to effectively find their intersection.

minitejpar
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Heres the question:
Let {u,v,w} be a linearly independent set of vectors of R^4. Let E = span{u,2v} and F=span{w,v}. Find EnF and E + F.


i really have no idea other than i guess if 1/2u=w and v=v, then the EnF can be defined by that, but I'm not sure if that is right! :(
 
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if u & v are linearly independent, what does span{u,v} represent?

now does span{u,2v} contain v?
 
span{u,v} represents all the combinations of u and v. (at least that's what i understand).

and yes, span(u,2v) does contain v, and so can i multiply 2v by 1/2? and then have span{u,v} instead of span{u,2v}?

if this is the case, then how do i find the intersect if F=span{w,v} seeing as w is not u..?
 
minitejpar said:
span{u,v} represents all the combinations of u and v. (at least that's what i understand).
Can you be a bit more specific as to what you mean by "combination"?
and yes, span(u,2v) does contain v, and so can i multiply 2v by 1/2? and then have span{u,v} instead of span{u,2v}?

if this is the case, then how do i find the intersect if F=span{w,v} seeing as w is not u..?
When a vector x is in E ∩ F, that means x∈E and x∈F. So you're looking for all vectors that can be expressed as a combination of u and 2v (so that it's in E) and a combination of w and v (so that it's in F). So again, it depends on what exactly you mean by "combination."
 
minitejpar said:
span{u,v} represents all the combinations of u and v. (at least that's what i understand).
span{u,v} = the set containing all linear combinations of u & v, so any vector w with:
w = a.u + b.v
for any real scalars a,b

think of u & v as vectors, what does span{u,v} represent geometrically?

note that
0 = 0.u + 0.v is in span{u,v}

minitejpar said:
and yes, span(u,2v) does contain v, and so can i multiply 2v by 1/2? and then have span{u,v} instead of span{u,2v}?
so then can you show

span{u,v} = span{u,2v}
minitejpar said:
if this is the case, then how do i find the intersect if F=span{w,v} seeing as w is not u..?
 
Your very very first step should be E = span{u, 2v} = span{u, v}. This makes life easier.
 
E + F = span{u,2v) + span{w,v} = au + 2bv + cw + dv = span(u,v,w) I think. Not comepletely sure.
 

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