Finding the Limit of a Multivariable Function at (0,0)

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SUMMARY

The limit of the multivariable function (y^2)(sin^2x) /(x^4+y^4) as (x,y) approaches (0,0) evaluates to 0 when approaching along the axes (x,0) and (0,y). However, when approaching along the line x=y, the limit becomes 1/2, indicating that the limit is path-dependent. This discrepancy confirms that the limit does not exist at the point (0,0).

PREREQUISITES
  • Understanding of multivariable calculus concepts, specifically limits.
  • Familiarity with trigonometric limits, particularly lim_{x→0} (sin x)/x.
  • Knowledge of L'Hôpital's Rule for evaluating indeterminate forms.
  • Proficiency in manipulating algebraic expressions involving limits.
NEXT STEPS
  • Study the concept of path-dependent limits in multivariable calculus.
  • Learn about L'Hôpital's Rule and its application in multivariable contexts.
  • Explore the epsilon-delta definition of limits for multivariable functions.
  • Investigate other examples of limits that exhibit path dependence.
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Students studying multivariable calculus, educators teaching limit concepts, and anyone interested in understanding the behavior of functions near critical points.

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Homework Statement


lim of (y^2)(sin^2x) /(x^4+y^4) as (x,y) approaches (0,0)


Homework Equations





The Attempt at a Solution



I got the limit as (x,y) approaches (0,y) and as (x,y) approaches (x,0), and it equals 0. But now I'm unsure of what to to next. I think it was the limit as (x,y) approaches (x,x) when x=y, but i get sin^2x / 2x^2
 
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[tex]\lim_{x\to 0}\frac{\sin^2x}{2x^2}=\frac{1}{2}\lim_{x\to 0}\left(\frac{\sin x}{x}\right)^2=\frac{1}{2}[/tex]
 

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