Finding the Limit of a Summation with Infinite Terms

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SUMMARY

The discussion focuses on finding the limit of the summation of the series defined by the formula ∞ lim (sum)(1/n^2) as n approaches infinity. Participants clarify that the limit of 1/n^2 as n approaches infinity is indeed 0, but the summation of the series converges to a specific value. The final solution to the summation is known to be π²/6, a well-established result in mathematical analysis.

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Homework Statement



lim "sum"(1/n^2)
n→∞ n=0

Can you help me find the final solution?


The Attempt at a Solution



lim (1/n^2) = 0 ?
n-∞

But the "sum" confuses
 
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Lim_{n \rightarrow \infty} \Sigma \left( \frac{1}{n^{2}}\right) So sum each successive term \frac{1}{1}+\frac{1}{2^{2}}+\frac{1}{3^{2}}+\frac{1}{4^{2}}+\frac{1}{5^{2}}...
 
Last edited:
There must be a way to find a final solution (with only one number).
Anybody?
 

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