Finding the local minimum of a graph

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The discussion revolves around identifying local minimums on a provided graph, with initial claims of local minima at x=0, 2, and 5, while the answer key suggests they are at 1, 2, and 5. Clarification is sought on why x=1 qualifies as a local minimum despite being a discrete point. The definition of a local minimum is emphasized, indicating that the y-value at a local minimum must be lower than nearby y-values. The conversation also touches on the misconception that x=6 could be a local minimum, clarifying that it is actually a local maximum. Understanding local minima requires careful analysis of surrounding values, regardless of continuity.
JustinLiang
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Homework Statement


The question provides a graph and asks for the local minimums. I attached a picture with the graph.

2. The attempt at a solution
I said the local minima are when x=0,2,5.

However the answer key suggests they are at 1,2,5.
Could someone please explain why 1 is a local minimum? It is just a point on the graph...
Maybe the answer key is wrong.
 

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Recall how "local minimum" is defined.

ehild
 
ehild said:
Recall how "local minimum" is defined.

ehild

So local minimum tells us that a y value near the point is always greater than the y value of the point. That is why we can call it the local minimum. However, in this case the dot is no continuous, so there is no y value near it to compare?

I understand why 0 cannot be a local minimum but I fail see see why 1 can be.
 
Are the y(x) values near to x=1 higher than y(1)? The function does not need to be continuous to have a local minimum. ehild
 
ehild said:
Are the y(x) values near to x=1 higher than y(1)? The function does not need to be continuous to have a local minimum.


ehild

Ah okay, but what about x=6? Values near it are both lower, isn't that a local minimum then?
 
If all values near x=6 are lower than y(6) so y(6) is higher then anything else nearby, is it a minimum?

ehild
 
JustinLiang said:
Ah okay, but what about x=6? Values near it are both lower, isn't that a local minimum then?
No, its a local maximum!
 
HallsofIvi,

I know that you know it, (and I hope you think that I also know it) but I asked the OP...:wink:


ehild
 

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