Finding the magnetic vector potential

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SUMMARY

The discussion focuses on determining the magnetic vector potential for an electromagnetic wave represented by the electric field vector \(\vec{E} = E_0 \cos(kz - \omega t)(\hat{x} + \hat{y})\). The magnetic field is derived using the relation \(\vec{B} = \frac{1}{c} \hat{k} \times \vec{E}\), resulting in \(\vec{B} = \frac{E_0}{c} \cos(kz - \omega t)(\hat{y} - \hat{x})\). To find the potentials, it is essential to consider the absence of free charge and current density, leading to the assumption of \(\rho = 0\) and \(\vec{J} = 0\). The discussion emphasizes the importance of understanding the relevant equations relating fields to potentials and the need to consider the gauge due to time-varying fields.

PREREQUISITES
  • Understanding of electromagnetic wave equations
  • Familiarity with vector calculus
  • Knowledge of magnetic vector potential concepts
  • Experience with gauge choices in electromagnetism
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  • Review the derivation of the magnetic vector potential from electric and magnetic fields
  • Study the implications of gauge invariance in electromagnetic theory
  • Learn about the Lorenz gauge and its application to time-varying fields
  • Explore the relationship between electric field lines and potential functions in non-constant fields
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Je m'appelle
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I'm supposed to find the magnetic field, the scalar electric potential and magnetic vector potential for the following electromagnetic wave:

\vec{E} = E_0 cos (kz - \omega t) \left \{ \hat{x} + \hat{y} \right \}

Alright, the magnetic field goes as

\vec{B} = \frac{1}{c} \hat{k} \times \vec{E}

\vec{B} = \frac{E_0}{c} cos (kz - \omega t) \left \{ \hat{z} \times \hat{x} + \hat{z} \times \hat{y} \right \}

\vec{B} = \frac{E_0}{c} cos (kz - \omega t) \left \{ \hat{y} - \hat{x} \right \}

I used \hat{k} = \hat{z} since the wave seems to be traveling through the z-axis.

Now when it comes to the potentials, I'm lost. I know, for once, that I can't directly apply V = - \int \vec{E} . \vec{d \ell} since the electric field is no longer constant.

Any hints?
 
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You need the additional information about the presence of free charge and current density to solve for the potentials.
 
These are vacuum solutions of the wave equation, so you can assume ##\rho=0## and ##\vec{J}=0##.

A good place to start (and the reason the template you deleted is supposed to be there) is to find the relevant equations which relate the fields to the potentials.
 
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Je m'appelle said:
Now when it comes to the potentials, I'm lost. I know, for once, that I can't directly apply V = - \int \vec{E} . \vec{d \ell} since the electric field is no longer constant.

For the line integral V = - \int \vec{E} . \vec{d \ell}, you do not need a constant function to do the integral (maybe review some vector calculus?). You also need to consider what gauge you're using since you have time varying fields.
 

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