Finding the Maximum Value of a Tricky Function?

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SUMMARY

The maximum value of the function f(x) = 1/(1+|x|) + 1/(1+|x-a|), where a > 0, is definitively (2+a)/(1+a). Analysis of the first derivative reveals no roots for the intervals 0 <= x and a <= x, while the critical point at x = a/2 yields a minimum value of f(a/2) = 0. This confirms that the maximum occurs outside these intervals. The solution was verified using Wolfram Alpha for derivative calculations.

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gummz
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Homework Statement



f(x) = 1/(1+|x|) + 1/(1+|x-a|), a>0

I am to show that the maximum value of this function is (2+a)/(1+a).

Homework Equations



None in particular. Derivatives for 1/x and the chain rule for f(g(x)).

The Attempt at a Solution



I have parted this function according to 0 <= x, 0 <= x <= a, a <= x, and differentiated and confirmed via Wolfram Alpha.

The first derivative has no root for 0 <= x and a <= x, and for 0 <= x <= a I get the value x = a/2, which yields f(a/2) = 0, which is obviously a minimum and not a maximum.
 
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gummz said:

Homework Statement



f(x) = 1/(1+|x|) + 1/(1+|x-a|), a>0

I am to show that the maximum value of this function is (2+a)/(1+a).

Homework Equations



None in particular. Derivatives for 1/x and the chain rule for f(g(x)).

The Attempt at a Solution



I have parted this function according to 0 <= x, 0 <= x <= a, a <= x, and differentiated and confirmed via Wolfram Alpha.

The first derivative has no root for 0 <= x and a <= x, and for 0 <= x <= a I get the value x = a/2, which yields f(a/2) = 0, which is obviously a minimum and not a maximum.

OK, so what are these facts telling you?
 
gummz said:
f(x) = 1/(1+|x|) + 1/(1+|x-a|), a>0
I get the value x = a/2, which yields f(a/2) = 0, which is obviously a minimum and not a maximum.
Double check your evaluation at x=a/2. It seems like you took the right approach. Also, don't hesitate to plot the function with an arbitrary value a.
 

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