Finding the nth Exponent: Solving for n in 2^2^n = 36 trillion

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Homework Help Overview

The problem involves solving for n in the equation 2^2^n = 36 trillion, which falls under the subject area of exponential equations and logarithmic functions.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss various methods of taking logarithms to solve for n, with some suggesting the need to take logs twice. There are differing values for n proposed, with attempts to clarify the steps involved in the logarithmic manipulation.

Discussion Status

The discussion is active, with participants sharing their calculations and questioning each other's approaches. Some guidance has been offered regarding the correct application of logarithmic properties, and there is an acknowledgment of confusion around the manipulation of exponents.

Contextual Notes

Participants are navigating through the complexities of logarithmic identities and the implications of their calculations. There is a noted uncertainty regarding the correct interpretation of the original equation and the steps taken to isolate n.

MrAnderson
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Homework Statement


find n.



Homework Equations


2^2^n = 36trillion



The Attempt at a Solution


I have worked this out and found n to be equal to 3.67 can someone confirm that i have the right solution? I took the log on both sides and worked it out.
 
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I get n ~ 5.4929. You have to take the log of both sides twice.
For my value of n, 2^n ~ 45.03, and 2 to that power is close to 36 trillion.
 
Mark44 said:
I get n ~ 5.4929. You have to take the log of both sides twice.
For my value of n, 2^n ~ 45.03, and 2 to that power is close to 36 trillion.

That's correct that 2^n = 36trillion and n=45, i get this also. But when i attempt to get n when 2^2^n = 36 trillion i first convert 2^nlog2 =log(36trillon)
which becomes log 2^nlog2 =log(log(36 trillion)), now at this point i divide both sides by log2. Now I am totally stuck and lost. Can you explain the process?
 
2^(2^n) = 36 x 10^12
==> (2^n) log 2 = log(36 x 10^12)
==> n log(2) + log(log 2) = log(log(36 x 10^12))

Now, subtract log(log 2) from both sides, and then divide both sides by log(2).

I think you did something weird with the exponents when you got 2^nlog2. The exponent on 2 of your original express is 2^n, so when you take the log of 2^2^n, you get 2^n * log 2, and not what you show.
 
Mark44 said:
2^(2^n) = 36 x 10^12
==> (2^n) log 2 = log(36 x 10^12)
==> n log(2) + log(log 2) = log(log(36 x 10^12))

Now, subtract log(log 2) from both sides, and then divide both sides by log(2).

I think you did something weird with the exponents when you got 2^nlog2. The exponent on 2 of your original express is 2^n, so when you take the log of 2^2^n, you get 2^n * log 2, and not what you show.

Oh i see, you have to add them and then subtract them then divide by log(2). thanks a lot, you've been very helpfull :).
 

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