The problem involves the equation 6^log x = 1/36, which is situated within the context of logarithmic functions and exponentiation. Participants are exploring the implications of this equation and the relationship between the logarithm and its base.
The discussion is ongoing, with various interpretations being explored. Some participants have offered guidance on taking logarithms and considering the base, while others express uncertainty about the correct approach and the implications of their calculations.
There is a noted lack of clarity regarding the base of the logarithm, which is not specified in the problem statement. This has led to differing assumptions among participants about how to proceed with the solution.
Coco12 said:Homework Statement
6^log x=1/36
2. Homework Equations
Y=logcx
The Attempt at a Solution
How do u solve this? I know the 1/36 is the exponent. Usually the logs that u normally do is not in an exponent like this. The answer is 0.01. How did they get that?
Coco12 said:I thought the ans was -2 since 6^-2 = 1/36
But the ans is 0.01. So that means it is not...
Coco12 said:Is the base 10?