 #1
PhysicsTest
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 15
 Homework Statement:

Prove that the concentration n of free electrons per cubic meter of a metal is given by
n = d*v/AM = A0dv*10^3/A
where d = density, kg/m^3
v = valence, free electrons per atom
A = atomic weight
M = weight of atom of unit atomic weight, kg
A0 = Avogadro's number, molecules/mole
 Relevant Equations:
 1gram = A*1amu
The required number of free electrons to be calculated is
##n = \frac{dv} {AM} = \frac{A_0dv*10^3} {A} ##
I know mass of single atom is ##M##
The atomic weight of mole of atoms is ##A##.
Hence ##A = A_0*M ##
##d = \frac{A} {1} ## > "1" represents ##1m^3##. I am confused how to proceed further. How do i approach?
##n = \frac{dv} {AM} = \frac{A_0dv*10^3} {A} ##
I know mass of single atom is ##M##
The atomic weight of mole of atoms is ##A##.
Hence ##A = A_0*M ##
##d = \frac{A} {1} ## > "1" represents ##1m^3##. I am confused how to proceed further. How do i approach?