1. The problem statement, all variables and given/known data Find the point on the graph y = sqrt 2x-1 where the tangent line is parallel to x - 3y = 16 2. Relevant equations 3. The attempt at a solution So what I started off was was trying to find the slope of x - 3y = 16. I rearranged the equation to a y = equation and got 16-x /-3 which I got a slope of -3. Then I went to find the deriviative of y = sqrt 2x-1 which I get (x - 1/2)exp-1/2 From there i get a little lost. The derivative = the slope of the tangent which would get me my x and y points, but my x values get a lot wonky. Would somebody be able to lead me in the right direction of finding my x point? Thanks!